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Calc BC Key Vocab 3

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Across
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∫ √(1 + (dy/dx)²) dx
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Using a tangent line to approximate values of the function
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∫ f(x) dx on interval a to b = F(b) - F(a)
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the highest point over the entire domain of a function
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g'(x) = 1/ f'(g(x))
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0<An<Bn - if the sum of Bn converges, then the sum of An converges
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alternating series converges and general term converges with another test
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using rectangles with left-endpoints to evaluate integral
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pi∫f(x)^2dx
Down
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lim x→c f(x) exists, f(c) exists, lim x→c f(x) = f(c)
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If f is continuous on [a,b] and differentiable on (a,b) and if f(a)=f(b), then there is at least one number c on (a,b) such that f'(c)=0
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If f is continuous on an open interval containing a, then for every x in the interval the derivative of the the integral of f(x) dx on the interval is equal to f(x)
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1/ (b-a) ∫ f(x) dx (from a to b)
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has limits a and b